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烟气量及焓的计算

2023-04-13 来源:钮旅网


烟气量及焓的计算

枣林:

燃料燃烧所需理论空气量:

1n,,0V,0.5H,0.5CO,(m,)CH,1.5HS,O ,k2mn22,,214,,

133 ,,,,0.5,0,0.5,0,2,10.96,1.5,0,10.9,0.52m/m21

Vk 取1.05 ,,,0Vk

33则: V,1.05,0.52,0.55m/mk

燃料燃烧产生烟气量:

V,V,V,0.01(CO,CO,mCH,HS)二氧化碳和二氧化硫: ,ROCOSO2mn2222

33 ,0.01,(1.68,0,1,10.96,0),0.13m/m

n,,00V,0.01,H,HS,,CH,120,(d,Vd)水蒸气: ,HOmnrkk222,,2,,

取值0.01和0.58 d,drk

033V,0.01,,,0,0,2,10.96,120,(0.01,0.52,0.58),0.59m/m则: HO2

0033V,0.79V,0.008N,0.79,0.52,0.008,76.46,1.02m/m氮气: Nk22

烟气的焓:

内差法计算出600?时1m3气体、空气的焓:

(c,)(c,)(c,)(c,),CONHOk(?) 222(kJ/m3) (kJ/m3) (kJ/m3) (kJ/m3)

600 1216 886 1017 906

003空气焓: I,V(c,),0.52,906,471.12kJ/mkkk

烟气焓

0003I,V(c,),V(c,),V(c,),0.13,1216,1.02,886,0.59,1017,1661.83kJ/myRORONNHOHO222222

当>1时: ,

00o3I,I,,I,I,(,,1)I,1661.83,(1.05,1),471.12,1685.39kJ/m yykyk

刘家:

燃料燃烧所需理论空气量:

1n,,0V,0.5H,0.5CO,(m,)CH,1.5HS,O ,k2mn22,,214,,

133 ,,,,0.5,0,0.5,0,2,11.19,1.5,0,12.06,0.49m/m21

Vk 取1.05 ,,,0Vk

33则: V,1.05,0.49,0.51m/mk

燃料燃烧产生烟气量:

V,V,V,0.01(CO,CO,mCH,HS)二氧化碳和二氧化硫: ,ROCOSO2mn2222

33 ,0.01,(1.79,0,1,11.19,0),0.13m/m

n,,00V,0.01,H,HS,,CH,120,(d,Vd)水蒸气: ,HOmnrkk222,,2,,

取值0.01和0.58 d,drk

033V,0.01,,,0,0,2,11.19,120,(0.01,0.49,0.58),0.58m/m则: HO2

0033V,0.79V,0.008N,0.79,0.49,0.008,74.96,0.99m/m氮气: Nk22

烟气的焓:

内差法计算出600?时1m3气体、空气的焓:

(c,)(c,)(c,)(c,),CONHOk(?) 222(kJ/m3) (kJ/m3) (kJ/m3) (kJ/m3)

600 1216 886 1017 906

003空气焓: I,V(c,),0.49,906,443.94kJ/mkkk

烟气焓

0003I,V(c,),V(c,),V(c,),0.13,1216,0.99,886,1017,1625.08kJ/myRORONNHOHO222222当>1时: ,

00o3I,I,,I,I,(,,1)I,1625.08,(1.05,1),443.94,1647.28kJ/m yykyk

0.58,

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